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Cord Fuel Wood

Reference data and engineering information about cord fuel wood for material properties applications.

cordfuelwood

Overview

Engineering reference data for Cord Fuel Wood in material science and properties.

Key Formulas

Stress

σ=FA\sigma = \frac{F}{A}

Force per unit area.

Strain

ε=ΔLL0\varepsilon = \frac{\Delta L}{L_0}

Change in length per original length.

Hooke's Law

σ=Eε\sigma = E \varepsilon

Stress proportional to strain in elastic region.

Thermal Expansion

ΔL=αL0ΔT\Delta L = \alpha L_0 \Delta T

Length change due to temperature.

Variables

SymbolDescriptionUnit
σ\sigmaStressPa
ε\varepsilonStrain
EEYoung's modulusPa
α\alphaThermal expansion coefficient1/°C
ΔT\Delta TTemperature change°C

Firewood Types and Properties

When purchasing firewood, the type of wood affects burning performance and characteristics. The air space within a standard cord can constitute up to 40% of the total volume, leading to a net wood volume that typically ranges from 80 to 100 cubic feet per cord.

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Typical Firewood Types and Their Characteristics
Firewood Type
Wood Type
Description
Ash, whiteHardwoodGood firewood
BeechHardwoodGood firewood
Birch, yellowHardwoodGood firewood
ChestnutHardwoodExcessive sparking, can be dangerous
CottonwoodHardwoodGood firewood
Elm, whiteHardwoodDifficult to split, burns well
HickoryHardwoodSlow steady fire, best firewood
Maple, sugarHardwoodGood firewood
Oak, redHardwoodSlow steady fire
Oak, whiteHardwoodSlow steady fire
Pine, yellowSoftwoodQuick hot fire, smokier than hardwood
Pine, whiteSoftwoodQuick hot fire, smokier than hardwood
Walnut, blackHardwoodGood firewood

Source: engineeringtoolbox.com

Cord Calculation Examples

To calculate the number of cords in a firewood pile, measure the length (ll), width (ww), and height (hh), then compute the volume and divide by the appropriate cord volume.

Example 1 (Imperial Units): A pile is 12 ft long, 2.5 ft wide, and 6 ft high. N=(12ft)×(2.5ft)×(6ft)128ft3=1.4cordN = \frac{(12 \, \text{ft}) \times (2.5 \, \text{ft}) \times (6 \, \text{ft})}{128 \, \text{ft}^3} = 1.4 \, \text{cord}

Example 2 (Metric Units): A pile is 6 m long, 1.2 m wide, and 1.5 m high. N=(6m)×(1.2m)×(1.5m)3.62m3=3cordN = \frac{(6 \, \text{m}) \times (1.2 \, \text{m}) \times (1.5 \, \text{m})}{3.62 \, \text{m}^3} = 3 \, \text{cord}

References