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Discharge Height Vertical Pipe

Reference data and engineering information about discharge height vertical pipe for fluid mechanics applications.

dischargeheightverticalpipe

Overview

Engineering reference data for Discharge Height Vertical Pipe in fluid mechanics.

Key Formulas

Reynolds Number

Re=ρvDμRe = \frac{\rho v D}{\mu}

Ratio of inertial to viscous forces — determines flow regime.

Bernoulli's Equation

P+12ρv2+ρgh=constP + \frac{1}{2}\rho v^2 + \rho g h = \text{const}

Conservation of energy for steady, inviscid, incompressible flow.

Continuity Equation

A1v1=A2v2A_1 v_1 = A_2 v_2

Conservation of mass for incompressible flow.

Darcy-Weisbach

ΔP=fLDρv22\Delta P = f \frac{L}{D} \frac{\rho v^2}{2}

Pressure drop due to friction in a pipe.

Variables

SymbolDescriptionUnit
ReReReynolds number
ρ\rhoFluid densitykg/m³
vvFlow velocitym/s
DDCharacteristic dimensionm
μ\muDynamic viscosityPa·s
PPPressurePa
ffDarcy friction factor

Main Formulas

The maximum discharge height (h) for water flowing from a vertical pipe can be calculated with the following formulas:

Imperial Units: h=(Q5.68kd2)2h = \left( \frac{Q}{5.68 \cdot k \cdot d^2} \right)^2 where:

  • h = discharge height (inches)
  • Q = flow (gpm)
  • d = pipe diameter (inches)
  • k = coefficient (dimensionless, ranges 0.87 - 0.97)

Rearranged for Flow (Q): Q=5.68kd2hQ = 5.68 \cdot k \cdot d^2 \cdot \sqrt{h}

Example Calculation

To estimate flow from a vertical 4-inch pipe with a measured discharge height of 3 ft (36 inches) and a coefficient k = 0.97: Q=5.68×0.97×(4 in)2×36 inQ = 5.68 \times 0.97 \times (4\ \text{in})^2 \times \sqrt{36\ \text{in}} Q529 gpmQ \approx 529\ \text{gpm}

Coefficient k

The coefficient kk is an empirical factor that accounts for flow characteristics. For this application, it typically ranges from *0.87 to 0.97. A value of *0.96 is often used as a default for calculations.

Unit Conversions

Key conversion factors for the Imperial system:

  • 1 in=25.4 mm1\ \text{in} = 25.4\ \text{mm}
  • 1 gal (US)/min=6.30888×105 m3/s1\ \text{gal (US)/min} = 6.30888 \times 10^{-5}\ \text{m}^3/\text{s}
  • 1 gal (US)/min=0.06309 dm3/(liters/s)1\ \text{gal (US)/min} = 0.06309\ \text{dm}^3/\text{s}\ (\text{liters}/\text{s})
  • 1 gal (US)/min=0.227 m3/h1\ \text{gal (US)/min} = 0.227\ \text{m}^3/\text{h}

References