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Electric Resistance Wires

Reference data and engineering information about electric resistance wires for electrical applications.

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Overview

Engineering reference data for Electric Resistance Wires in electrical engineering.

Key Formulas

Ohm's Law

V=IRV = IR

Voltage = Current × Resistance.

Power

P=VI=I2R=V2/RP = VI = I^2R = V^2/R

Electrical power.

Energy

E=PtE = Pt

Energy = Power × Time.

Variables

SymbolDescriptionUnit
VVVoltageV
IICurrentA
RRResistanceΩ
PPPowerW

Data Table: Nickel-Chromium Heater Wire Specifications

20 rows
Nickel-Chromium Heater Wire: Diameter, Resistance per Meter, and Maximum Current for Temperature Rises.
SWG
Diameter(mm)
Diameter(in)
Resistance(ohm/m)
Current @ 500°C(A)
Current @ 1000°C(A)
122.6420.1040.1973878
142.0320.0800.3332653
161.6260.0640.5201940
181.2190.0480.921327
200.9140.0361.658.518
220.7110.0282.726.313
240.5590.0224.404.59.5
260.4570.0186.603.57.0
280.3760.01489.72.75.5
300.3150.012413.92.24.5
320.2740.010818.31.93.5
340.2340.009225.21.63.0
360.1930.007637.01.32.3
380.1520.006059.01.01.7
400.1220.0048920.81.4
420.1020.00401330.651.1
440.08130.0032208--
460.06100.0024370--
480.04060.0016835--
500.02540.00102130--

Source: engineeringtoolbox.com

Key Formulas in Example

The example calculation for heater wire length uses the following fundamental relationships derived from Ohm's Law and electrical power:

  1. Electric Power: P=UIP = U \cdot I
  2. Current: I=PUI = \frac{P}{U}
  3. Resistance (Ohm's Law): R=UIR = \frac{U}{I}
  4. Wire Length from Total Resistance: l=RtotalRper meterl = \frac{R_{\text{total}}}{R_{\text{per meter}}} Where RtotalR_{\text{total}} is the required total resistance of the heater element, and Rper meterR_{\text{per meter}} is the resistance per unit length of the chosen wire.

Worked Example

Goal: Calculate the length of an 18 SWG nickel-chromium wire for an electric heater rated at 2000 W on a 230 V supply, with a maximum wire temperature of 500°C.

Steps:

  1. Find Required Current: I=PU=2000 W230 V=8.7 AI = \frac{P}{U} = \frac{2000 \text{ W}}{230 \text{ V}} = 8.7 \text{ A} Check: From the table, 18 SWG wire can handle up to 13 A at 500°C. 8.7 A is within the safe operating limit.

  2. Find Total Required Resistance: Rtotal=UI=230 V8.7 A=26.4 \OmegaR_{\text{total}} = \frac{U}{I} = \frac{230 \text{ V}}{8.7 \text{ A}} = 26.4 \text{ \Omega}

  3. Find Resistance per Meter: From the data table, the resistance for 18 SWG wire is 0.92 \Omega/m0.92 \text{ \Omega/m}.

  4. Calculate Wire Length: l=RtotalRper meter=26.4 \Omega0.92 \Omega/m=28.7 ml = \frac{R_{\text{total}}}{R_{\text{per meter}}} = \frac{26.4 \text{ \Omega}}{0.92 \text{ \Omega/m}} = 28.7 \text{ m}

Result: Approximately 28.7 meters of 18 SWG nickel-chromium wire are required.

Definitions and Notes

  • SWG (Standard Wire Gauge): An imperial system for specifying wire diameter, historically used in the UK and Commonwealth countries.
  • Nickel-Chromium (NiCr): A family of alloys (often branded as Nichrome) characterized by high electrical resistance, high melting point, and good corrosion resistance at elevated temperatures. These properties make them ideal for heating elements.
  • Temperature Rise vs. Current: The table shows that for a given wire gauge, a higher current is required to achieve a higher temperature rise. For a fixed current, a thinner wire (higher SWG number) will reach a higher temperature due to its higher resistance per unit length.

Interactive Charts

AWG Wire Gauge Chart & Table – American Wire Gauge (AWG) Standards

References