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Energy Storage Water

Reference data and engineering information about energy storage water for water systems applications.

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Overview

Engineering reference data for Energy Storage Water in water systems.

Key Formulas

Hydrostatic Pressure

P=ρghP = \rho g h

Pressure due to water column.

Flow Rate

Q=AvQ = A v

Area × velocity.

Variables

SymbolDescriptionUnit
PPPressurePa
QQFlow ratem³/s
hhHead/depthm

Calculation Examples

The energy stored in water can be calculated using the formula E=cpΔtmE = c_p \Delta t m, where cpc_p is the specific heat of water, Δt\Delta t is the temperature difference, and mm is the mass of water.

Example 1: Hot Water Tank

A 1000-liter water tank is heated to 90°C with a surrounding temperature of 20°C. The energy stored is calculated as follows:

E=cpΔtm=(4.2kJ/kg°C)×(90°C20°C)×(1000kg)=294,000kJE = c_p \Delta t m = (4.2 \, \text{kJ/kg°C}) \times (90°C - 20°C) \times (1000 \, \text{kg}) = 294,000 \, \text{kJ}

Converting to kilowatt-hours:
294,000kJ×13600h/s=81.7kWh294,000 \, \text{kJ} \times \frac{1}{3600} \, \text{h/s} = 81.7 \, \text{kWh}

Example 2: Solar Water Tank

A 200 US gallon solar water buffer tank is heated to 200°F. Using cp=1Btu/lb°Fc_p = 1 \, \text{Btu/lb°F} and water density ρ=8.3lbm/US gallon\rho = 8.3 \, \text{lbm/US gallon}:

m=200US gallons×8.3lbm/US gallon=1660lbmm = 200 \, \text{US gallons} \times 8.3 \, \text{lbm/US gallon} = 1660 \, \text{lbm}

E=cpΔtm=(1Btu/lb°F)×(200°F)×1660lbm=332,000BtuE = c_p \Delta t m = (1 \, \text{Btu/lb°F}) \times (200°F) \times 1660 \, \text{lbm} = 332,000 \, \text{Btu}

Energy Unit Conversions

Common energy unit conversions for reference:

  • 1 Joule (J) = 0.1020 kpm = 2.778×1072.778 \times 10^{-7} kWh = 2.389×1042.389 \times 10^{-4} kcal = 0.7376 ft·lbf = 1 kg·m²/s² = 1 watt-second = 1 N·m = 1 ft·lb = 9.478×1049.478 \times 10^{-4} Btu

  • 1 British Thermal Unit (Btu) = 1055.06 J = 107.6 kpm = 2.92875×1042.92875 \times 10^{-4} kWh = 251.996 calorie (IT) = 0.252 kcal = 777.649 ft·lbf

References