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Enthalpy Wet Steam

Reference data and engineering information about enthalpy wet steam for thermodynamics applications.

enthalpywetsteam

Overview

Engineering reference data for Enthalpy Wet Steam in thermodynamics.

Key Formulas

First Law

ΔU=QW\Delta U = Q - W

Energy is conserved — heat added minus work done.

Ideal Gas Law

PV=nRTPV = nRT

Relates pressure, volume, and temperature of an ideal gas.

Heat Transfer

Q=mcΔTQ = mc\Delta T

Sensible heat transfer.

Carnot Efficiency

η=1TC/TH\eta = 1 - T_C/T_H

Maximum efficiency between two temperatures.

Variables

SymbolDescriptionUnit
UUInternal energyJ
QQHeatJ
WWWorkJ
PPPressurePa
VVVolume
TTTemperatureK

Example: Wet Steam Enthalpy Calculation

Consider a practical scenario to illustrate the calculation of wet steam enthalpy. Suppose wet steam has a dryness fraction (ζ\zeta) of 0.8. From steam tables at the relevant pressure, the specific enthalpy of steam (hsh_s) is 2778 kJ/kg, and the enthalpy of saturated water (hwh_w) is 504 kJ/kg.

The enthalpy of wet steam (hth_t) is calculated using:

ht=hsζ+(1ζ)hwh_t = h_s \cdot \zeta + (1 - \zeta) \cdot h_w

Substituting the values:

ht=2778×0.8+(10.8)×504h_t = 2778 \times 0.8 + (1 - 0.8) \times 504

ht=2222.4+100.8=2323.2 kJ/kgh_t = 2222.4 + 100.8 = 2323.2 \text{ kJ/kg}

This result shows that wet steam with a dryness fraction of 0.8 has an enthalpy of 2323.2 kJ/kg, which is less than the enthalpy of dry saturated steam at the same pressure. Accurate determination of the dryness fraction is critical for efficient energy utilization in steam systems.

References