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Floor Loads Uniformly Concentrated

Reference data and engineering information about floor loads uniformly concentrated for mechanics applications.

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Overview

Engineering reference data for Floor Loads Uniformly Concentrated in mechanics.

Key Formulas

Newton's Second Law

F=maF = ma

Force = mass × acceleration.

Work

W=FdcosθW = Fd\cos\theta

Work = force × displacement × cos(angle).

Kinetic Energy

Ek=12mv2E_k = \frac{1}{2}mv^2

Energy of motion.

Potential Energy

Ep=mghE_p = mgh

Gravitational potential energy.

Variables

SymbolDescriptionUnit
FFForceN
mmMasskg
aaAccelerationm/s²
vvVelocitym/s

Typical Floor Loads

The following table provides typical concentrated and uniformly distributed floor loads for various building applications:

16 rows
Typical concentrated and uniformly distributed floor loads for various applications
Type of Application
Concentrated Load(kN)
Uniformly Distributed Load(kN/m²)
Bedroom, dwelling1.81.5
Bedroom, hotel1.82
Bathroom1.82
Balcony, dwelling1.41.5
Balcony, hotel or guest house1.53
Communal area1.41.5
Factory, general4.55
Kitchen, communal4.53
Laboratory4.53
Laundry4.53
Library4.54
Office2.72.5
WC1.82
Warehouse, general storage1.82
Work area, general2.72.5
Workshop4.55

Source: engineeringtoolbox.com

:::note For balconies in hotels or guest houses, the concentrated load of 1.5 kN is applied at the outer edge (as a line load), rather than as a point load. :::

Worked Example

Calculate the load from a 800 kg pallet:

Given:

  • Mass: m=800 kgm = 800 \text{ kg}
  • Gravitational acceleration: g=9.81 m/s2g = 9.81 \text{ m/s}^2

Applying the load conversion formula:

F=mg1000=800×9.811000=7.8 kNF = \frac{m \cdot g}{1000} = \frac{800 \times 9.81}{1000} = 7.8 \text{ kN}

The load from the 800 kg pallet is 7.8 kN.

Interactive Charts

Beams Supported at Both Ends with Continuous and Point Loads: Stress, Deflection, Formulas and Calculators

References