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Flow Section Channels

Reference data and engineering information about flow section channels for fluid mechanics applications.

flowsectionchannels

Overview

Engineering reference data for Flow Section Channels in fluid mechanics.

Key Formulas

Reynolds Number

Re=ρvDμRe = \frac{\rho v D}{\mu}

Ratio of inertial to viscous forces — determines flow regime.

Bernoulli's Equation

P+12ρv2+ρgh=constP + \frac{1}{2}\rho v^2 + \rho g h = \text{const}

Conservation of energy for steady, inviscid, incompressible flow.

Continuity Equation

A1v1=A2v2A_1 v_1 = A_2 v_2

Conservation of mass for incompressible flow.

Darcy-Weisbach

ΔP=fLDρv22\Delta P = f \frac{L}{D} \frac{\rho v^2}{2}

Pressure drop due to friction in a pipe.

Variables

SymbolDescriptionUnit
ReReReynolds number
ρ\rhoFluid densitykg/m³
vvFlow velocitym/s
DDCharacteristic dimensionm
μ\muDynamic viscosityPa·s
PPPressurePa
ffDarcy friction factor

Hydraulic Diameter

The hydraulic diameter DhD_h is an equivalent diameter used to characterize non-circular channels, defined as:

Dh=4APD_h = \frac{4A}{P}

where AA is the flow area and PP is the wetted perimeter. For a circular channel flowing full, DhD_h equals the actual diameter DD.

Channel-specific Hydraulic Diameter

Rectangular Channel: Dh=4bhb+2hD_h = \frac{4 b h}{b + 2 h}

Trapezoidal Channel: Dh=4(h(b+T)2)b+2(Tb2)2+h2D_h = \frac{4 \left( \frac{h(b + T)}{2} \right)}{b + 2 \sqrt{\left( \frac{T - b}{2} \right)^2 + h^2}}

Triangular Channel: Dh=4(zh2)2h1+z2=2zh1+z2D_h = \frac{4(z h^2)}{2h \sqrt{1 + z^2}} = \frac{2z h}{\sqrt{1 + z^2}}

Circular Channel (partially filled): Dh=4(D24(αsin(2α)2))αD=D(1sin(2α)2α)D_h = \frac{4 \left( \frac{D^2}{4} \left( \alpha - \frac{\sin(2\alpha)}{2} \right) \right)}{\alpha D} = D \left( 1 - \frac{\sin(2\alpha)}{2\alpha} \right)

Where α=cos1(1hr)\alpha = \cos^{-1}\left(1 - \frac{h}{r}\right) and r=D/2r = D/2.

Geometric Section Properties

4 rows
Summary of hydraulic properties for common channel geometries
Channel Shape
Flow Area (A)(m²/in²)
Wetted Perimeter (P)(m/in)
Hydraulic Radius (Rₕ)(m/in)
RectangularA = b hP = b + 2hRₕ = (b h)/(b + 2h)
TrapezoidalA = h(b + T)/2P = b + 2√[((T - b)/2)² + h²]Rₕ = [h(b + T)/2] / [b + 2√[((T - b)/2)² + h²]]
TriangularA = z h²P = 2h√(1 + z²)Rₕ = z h / [2√(1 + z²)]
CircularA = (D²/4)(α - sin(2α)/2)P = α DRₕ = (D/4)[1 - sin(2α)/(2α)]

Source: engineeringtoolbox.com

Note: For all channel shapes, the hydraulic diameter Dh=4RhD_h = 4R_h.

References