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Inclined Planes Forces

Reference data and engineering information about inclined planes forces for mechanics applications.

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Overview

Engineering reference data for Inclined Planes Forces in mechanics.

Key Formulas

Newton's Second Law

F=maF = ma

Force = mass × acceleration.

Work

W=FdcosθW = Fd\cos\theta

Work = force × displacement × cos(angle).

Kinetic Energy

Ek=12mv2E_k = \frac{1}{2}mv^2

Energy of motion.

Potential Energy

Ep=mghE_p = mgh

Gravitational potential energy.

Variables

SymbolDescriptionUnit
FFForceN
mmMasskg
aaAccelerationm/s²
vvVelocitym/s

Angle of Repose

When a body rests on an inclined plane and is in equilibrium (not sliding), the gravitational component down the slope is balanced by static friction. At this critical angle, the angle of repose relationship holds:

μ=FpFn=Wsin(α)Wcos(α)=tan(α)\mu = \frac{F_p}{F_n} = \frac{W \sin(\alpha)}{W \cos(\alpha)} = \tan(\alpha)

The angle of repose α\alpha equals the arctangent of the static friction coefficient:

αrepose=arctan(μ)\alpha_{repose} = \arctan(\mu)

This means the maximum stable angle depends only on the surface materials, not the object's mass.


Work and Power on Inclines

When moving an object along an inclined plane over a distance dd, the work done against gravity is:

W=FpdW = F_p \cdot d

The power required to maintain constant velocity vv along the incline is:

P=Wt=FpvP = \frac{W}{t} = F_p \cdot v

where t=d/vt = d / v is the travel time.


Example: Vehicle on Graded Roads

An electric car with mass m=2400 kgm = 2400\ \text{kg} travels d=1 kmd = 1\ \text{km} along inclines (neglecting rolling and air resistance).

InclinationSlope Angle α\alphaForce FpF_pWork (1 km)Power at 80 km/hPower at 60 km/h
5%2.86°2,051 N2,051 kJ45.6 kW34.1 kW
10%5.71°4,088 N4,088 kJ90.8 kW67.9 kW

Key insight: Doubling the road grade from 5% to 10% approximately doubles both the required force and power output.

References