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Mixing Fluids Temperature Mass

Reference data and engineering information about mixing fluids temperature mass for thermodynamics applications.

mixingfluidstemperaturemass

Overview

Engineering reference data for Mixing Fluids Temperature Mass in thermodynamics.

Key Formulas

First Law

ΔU=QW\Delta U = Q - W

Energy is conserved — heat added minus work done.

Ideal Gas Law

PV=nRTPV = nRT

Relates pressure, volume, and temperature of an ideal gas.

Heat Transfer

Q=mcΔTQ = mc\Delta T

Sensible heat transfer.

Carnot Efficiency

η=1TC/TH\eta = 1 - T_C/T_H

Maximum efficiency between two temperatures.

Variables

SymbolDescriptionUnit
UUInternal energyJ
QQHeatJ
WWWorkJ
PPPressurePa
VVVolume
TTTemperatureK

Worked Example: Step-by-Step Solution

The example from the overview section demonstrates the formulas in action. Let's break down the calculation for clarity:

Given:

  • Fluid 1 (Water): Mass m1=10kgm_1 = 10 \, \text{kg}, Temperature t1=10Ct_1 = 10^\circ \text{C}
  • Fluid 2 (Water): Mass m2=2kgm_2 = 2 \, \text{kg}, Temperature t2=100Ct_2 = 100^\circ \text{C}
  • Specific heat of water: c=4.2kJ/kgCc = 4.2 \, \text{kJ/kg} \cdot {}^\circ \text{C}

Step 1: Calculate Final Mass m=m1+m2=10kg+2kg=12kgm = m_1 + m_2 = 10 \, \text{kg} + 2 \, \text{kg} = 12 \, \text{kg}

Step 2: Calculate Final Temperature t=m1c1t1+m2c2t2m1c1+m2c2t = \frac{m_1 c_1 t_1 + m_2 c_2 t_2}{m_1 c_1 + m_2 c_2} t=(10kg)(4.2kJ/kgC)(10C)+(2kg)(4.2kJ/kgC)(100C)(10kg)(4.2kJ/kgC)+(2kg)(4.2kJ/kgC)t = \frac{(10 \, \text{kg})(4.2 \, \text{kJ/kg} \cdot {}^\circ \text{C})(10^\circ \text{C}) + (2 \, \text{kg})(4.2 \, \text{kJ/kg} \cdot {}^\circ \text{C})(100^\circ \text{C})}{(10 \, \text{kg})(4.2 \, \text{kJ/kg} \cdot {}^\circ \text{C}) + (2 \, \text{kg})(4.2 \, \text{kJ/kg} \cdot {}^\circ \text{C})} t=420kJ+840kJ42kJ/C+8.4kJ/C=1260kJ50.4kJ/C=25Ct = \frac{420 \, \text{kJ} + 840 \, \text{kJ}}{42 \, \text{kJ/}^\circ\text{C} + 8.4 \, \text{kJ/}^\circ\text{C}} = \frac{1260 \, \text{kJ}}{50.4 \, \text{kJ/}^\circ\text{C}} = 25^\circ \text{C}

The final mixture of 12 kg of water reaches an equilibrium temperature of 25°C.

Practical Applications & Considerations

The principle of energy conservation, which these formulas embody, is fundamental in many engineering disciplines:

  • HVAC Systems: Mixing hot and cold water streams to achieve a desired supply temperature for heating or cooling.
  • Chemical Process Engineering: Calculating reactor temperatures or cooling requirements when combining process streams.
  • Food & Beverage: Determining the temperature of combined ingredients during mixing or brewing processes.
  • Energy Systems: Analyzing the performance of heat exchangers or thermal storage tanks.

Important Note: The formulas assume no heat loss to the surroundings and no phase change (e.g., boiling or condensation) occurs during the mixing process. For real-world applications, a heat transfer coefficient may be needed to account for losses.

References