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Moment Elevation Angle Beam Drawbridge

Reference data and engineering information about moment elevation angle beam drawbridge for material properties applications.

momentelevationanglebeam

Overview

Engineering reference data for Moment Elevation Angle Beam Drawbridge in material science and properties.

Key Formulas

Stress

σ=FA\sigma = \frac{F}{A}

Force per unit area.

Strain

ε=ΔLL0\varepsilon = \frac{\Delta L}{L_0}

Change in length per original length.

Hooke's Law

σ=Eε\sigma = E \varepsilon

Stress proportional to strain in elastic region.

Thermal Expansion

ΔL=αL0ΔT\Delta L = \alpha L_0 \Delta T

Length change due to temperature.

Variables

SymbolDescriptionUnit
σ\sigmaStressPa
ε\varepsilonStrain
EEYoung's modulusPa
α\alphaThermal expansion coefficient1/°C
ΔT\Delta TTemperature change°C

Example Calculations

Horizontal Beam (α = 0°)

Given a 10-meter HE-B 340B steel beam with continuous mass m=134kg/mm = 134 \, \text{kg/m}:

  1. Resultant Force (Weight): F=mgL=(134kg/m)(9.81m/s2)(10m)=13,145NF = m \cdot g \cdot L = (134 \, \text{kg/m}) \cdot (9.81 \, \text{m/s}^2) \cdot (10 \, \text{m}) = 13,145 \, \text{N}

  2. Acting Distance (Center of Mass): a=L2=10m2=5ma = \frac{L}{2} = \frac{10 \, \text{m}}{2} = 5 \, \text{m}

  3. Moment at Support A: M=Fa=(13,145N)(5m)=65,725NmM = F \cdot a = (13,145 \, \text{N}) \cdot (5 \, \text{m}) = 65,725 \, \text{Nm}

Elevated Beam (α = 30°)

Using the same beam lifted at an angle α=30°\alpha = 30°:

  1. Acting Distance (Projected): aα=cos(α)L2=cos(30°)5m=4.330ma_\alpha = \cos(\alpha) \cdot \frac{L}{2} = \cos(30°) \cdot 5 \, \text{m} = 4.330 \, \text{m}

  2. Moment at Support A: Mα=Faα=(13,145N)(4.330m)=56,920NmM_\alpha = F \cdot a_\alpha = (13,145 \, \text{N}) \cdot (4.330 \, \text{m}) = 56,920 \, \text{Nm}

Elevation Angle Effects

The moment required to hold or control a drawbridge depends directly on the cosine of its lifting angle. This relationship has important practical implications:

  • Maximum Moment at Horizontal: The critical, maximum moment occurs when the bridge is horizontal (α=0°\alpha = 0°, since cos(0°)=1\cos(0°) = 1).
  • Reduced Moment with Elevation: As the bridge is raised, the effective lever arm aa decreases, reducing the required moment following cos(α)\cos(\alpha).
  • Percentage Reduction: The moment at any angle α\alpha as a percentage of the maximum horizontal moment is: Moment %=cos(α)×100%\text{Moment \%} = \cos(\alpha) \times 100\% For example, at 60°60°, the moment is cos(60°)=0.5\cos(60°) = 0.5, or 50% of the horizontal moment.

References