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Pulleys

Reference data and engineering information about pulleys for mechanics applications.

pulleys

Overview

Engineering reference data for Pulleys in mechanics.

Key Formulas

Newton's Second Law

F=maF = ma

Force = mass × acceleration.

Work

W=FdcosθW = Fd\cos\theta

Work = force × displacement × cos(angle).

Kinetic Energy

Ek=12mv2E_k = \frac{1}{2}mv^2

Energy of motion.

Potential Energy

Ep=mghE_p = mgh

Gravitational potential energy.

Variables

SymbolDescriptionUnit
FFForceN
mmMasskg
aaAccelerationm/s²
vvVelocitym/s

Pulley Configurations

Different pulley arrangements offer mechanical advantages by reducing the effort force required to lift a load.

Single Fixed Pulley:
Changes the direction of force but provides no mechanical advantage. The effort force equals the load. S=FS = F

Single Movable Pulley:
Provides a mechanical advantage of 2. The effort force is half the load. S=12FS = \frac{1}{2}F

Combined Pulley Systems (Block and Tackle):
Systems with multiple movable pulleys further reduce the required effort. For example, with two pulleys (as described), the advantage is 3. S=13FS = \frac{1}{3}F

General Block & Tackle Formula

For any block and tackle system, the required effort force accounts for friction and the number of supporting ropes.

S=Fμn=mgμnS = \frac{F}{\mu n} = \frac{m g}{\mu n}

Where:

  • S = effort force (N, lb)
  • F = load (N, lb)
  • m = mass being lifted (kg, slugs)
  • g = acceleration due to gravity (9.81 m/s², 32.17 ft/s²)
  • μ = mechanical efficiency of the system (0 < μ ≤ 1)
  • n = number of ropes supporting the load

Practical Example

Problem: Calculate the effort force for a pulley system with 4 supporting ropes, a friction efficiency of μ = 0.8, and a load of 100 kg.

Solution: S=(100kg)(9.81m/s2)(0.8)(4)=245.25N307NS = \frac{(100 \, \text{kg})(9.81 \, \text{m/s}^2)}{(0.8)(4)} = 245.25 \, \text{N} \approx 307 \, \text{N}

Note: The original text cited 307 N, which may reflect a specific efficiency or rounding convention.

References