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Pvc Schedule 40 Pipe Friction Loss Diagram

Reference data and engineering information about pvc schedule 40 pipe friction loss diagram for fluid mechanics applications.

pvcschedulepipefrictionData Table

Overview

Engineering reference data for Pvc Schedule 40 Pipe Friction Loss Diagram in fluid mechanics.

Key Formulas

Reynolds Number

Re=ρvDμRe = \frac{\rho v D}{\mu}

Ratio of inertial to viscous forces — determines flow regime.

Bernoulli's Equation

P+12ρv2+ρgh=constP + \frac{1}{2}\rho v^2 + \rho g h = \text{const}

Conservation of energy for steady, inviscid, incompressible flow.

Continuity Equation

A1v1=A2v2A_1 v_1 = A_2 v_2

Conservation of mass for incompressible flow.

Darcy-Weisbach

ΔP=fLDρv22\Delta P = f \frac{L}{D} \frac{\rho v^2}{2}

Pressure drop due to friction in a pipe.

Variables

SymbolDescriptionUnit
ReReReynolds number
ρ\rhoFluid densitykg/m³
vvFlow velocitym/s
DDCharacteristic dimensionm
μ\muDynamic viscosityPa·s
PPPressurePa
ffDarcy friction factor

Hazen-Williams Coefficient

The friction loss calculations for this PVC pipe are based on the Hazen-Williams Equation, which is a common empirical formula used for water flow in pipes. The key parameter for this material is the roughness coefficient.

c=140c = 140

Where:

  • c is the Hazen-Williams roughness coefficient for PVC pipe.

Flow Velocity Guidelines

For Schedule 40 PVC pipe, engineers should adhere to the following velocity constraints to balance hydraulic efficiency and pipe longevity:

  • Common operating range: Velocities between 7 to 10 ft/s are typical.
  • General maximum: Velocities above 5 ft/s should be avoided in most applications.

Unit Conversion Reference

The following table provides common unit conversions relevant to the friction loss calculations.

3 rows
Common unit conversions for water flow and pressure in pipe systems.
Quantity
Value
Notes
Flow Rate1 gal (US)/min= 6.30888×10⁻⁵ m³/s = 0.0227 m³/h = 0.06309 dm³/s = 2.228×10⁻³ ft³/s = 0.1337 ft³/min
Velocity1 ft/s= 0.3048 m/s
Pressure1 psi= 6,894.8 Pa = 6.895×10⁻³ N/mm² = 6.895×10⁻² bar

Source: engineeringtoolbox.com

References