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Specific Heat Metal Alloys

Reference data and engineering information about specific heat metal alloys for thermodynamics applications.

specificheatmetalalloysData Table

Overview

Engineering reference data for Specific Heat Metal Alloys in thermodynamics.

Key Formulas

First Law

ΔU=QW\Delta U = Q - W

Energy is conserved — heat added minus work done.

Ideal Gas Law

PV=nRTPV = nRT

Relates pressure, volume, and temperature of an ideal gas.

Heat Transfer

Q=mcΔTQ = mc\Delta T

Sensible heat transfer.

Carnot Efficiency

η=1TC/TH\eta = 1 - T_C/T_H

Maximum efficiency between two temperatures.

Variables

SymbolDescriptionUnit
UUInternal energyJ
QQHeatJ
WWWorkJ
PPPressurePa
VVVolume
TTTemperatureK

Metal Alloy Specific Heats

15 rows
Specific heat capacity of common metal alloys
Metal Alloy
Specific Heat (cp)(kJ/kg·K)
Specific Heat (cp)(Btu/(lb·°F))
Admiralty Brass0.380.09
Aluminum Bronze0.380.09
Ball metal0.360.086
Beryllium Copper0.420.1
Brass0.3770.09
Bronze0.4350.104
Hasteloy0.380.091
Inconel0.460.11
Incoloy0.50.12
Manganese Bronze0.380.09
Monel0.530.127
Nickel steel0.4560.109
Red Brass0.380.09
Solder 50/50 Sn Pb0.1670.04
Yellow Brass0.380.09

Source: engineeringtoolbox.com

Heating Energy

The energy required to heat a substance is calculated using:

q=cpmΔTq = c_p \cdot m \cdot \Delta T

Where:

  • qq is the heat energy required (kJ)
  • cpc_p is the specific heat capacity (kJ/kg·K)
  • mm is the mass (kg)
  • ΔT\Delta T is the temperature change (K or °C)

Example Calculation:
Heating 10 kg of bronze (cp=0.435c_p = 0.435 kJ/kg·K) from 20°C to 100°C (ΔT=80\Delta T = 80 K):

q=(0.435 kJ/kg⋅K)×(10 kg)×(80 K)=348 kJq = (0.435\ \text{kJ/kg·K}) \times (10\ \text{kg}) \times (80\ \text{K}) = 348\ \text{kJ}

Interactive Charts

Specific heat capacity of common metal alloys

References