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Standard Form Scientific Engineering Notation

Reference data and engineering information about standard form scientific engineering notation for standard organizations applications.

standardformscientificengineering

Overview

Engineering reference data for Standard Form Scientific Engineering Notation in standard organizations.

Key Formulas

ISO Standard

ISO  9001:2015ISO \; 9001:2015

Quality management systems.

ASTM Standard

ASTM  E8ASTM \; E8

Standard test methods for tension testing.

ANSI Standard

ANSI/ASME  B16.5ANSI/ASME \; B16.5

Pipe flanges and flanged fittings.

Variables

SymbolDescriptionUnit
ISOISOInternational Organization for Standardization
ASTMASTMAmerican Society for Testing and Materials
ANSIANSIAmerican National Standards Institute

Examples of Operations

Addition and Subtraction in Notation

Numbers must share the same exponent before combining. Example:

4.3×104+2.4×103=4.3×104+0.24×104=(4.3+0.24)×104=4.54×1044.3\times10^4 + 2.4\times10^3 = 4.3\times10^4 + 0.24\times10^4 = (4.3 + 0.24) \times 10^4 = 4.54 \times 10^4

Multiplication

When multiplying, add the exponents:

N1×10x×N2×10y=(N1×N2)×10x+yN_1 \times 10^x \times N_2 \times 10^y = (N_1 \times N_2) \times 10^{x+y}

Example:

4.3×104×2.4×103=(4.3×2.4)×104+3=10.32×1074.3\times10^4 \times 2.4\times10^3 = (4.3 \times 2.4) \times 10^{4+3} = 10.32 \times 10^7

Division

When dividing, subtract the exponent in the denominator from the exponent in the numerator:

N1×10xN2×10y=(N1N2)×10xy\frac{N_1 \times 10^x}{N_2 \times 10^y} = \left(\frac{N_1}{N_2}\right) \times 10^{x-y}

Example:

4.3×1042.4×103=(4.32.4)×1043=1.79×101\frac{4.3\times10^4}{2.4\times10^3} = \left(\frac{4.3}{2.4}\right) \times 10^{4-3} = 1.79 \times 10^1

Engineering Notation and SI Prefixes

Engineering notation's power-of-10 multiples of 3 correspond directly to common SI prefixes:

PrefixSymbolFactor
kilok10310^3
megaM10610^6
gigaG10910^9
millim10310^{-3}
microµ10610^{-6}

This allows convenient unit conversion, for example:

  • 4.7 kJ=4.7×103 J=4700 J4.7\text{ kJ} = 4.7 \times 10^3\text{ J} = 4700\text{ J}
  • 8 MV=8×106 V=8000000 V8\text{ MV} = 8 \times 10^6\text{ V} = 8\,000\,000\text{ V}

References