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Speclore

Stockpile Volume

Reference data and engineering information about stockpile volume for miscellaneous applications.

stockpilevolume

Overview

Engineering reference data for Stockpile Volume in miscellaneous.

Key Formulas

Unit Conversion

y=xky = x \cdot k

Multiply by conversion factor.

Linear Interpolation

y=y1+(xx1)(y2y1)x2x1y = y_1 + \frac{(x - x_1)(y_2 - y_1)}{x_2 - x_1}

Estimate between two known points.

Percentage

p=partwhole×100%p = \frac{\text{part}}{\text{whole}} \times 100\%

Part as fraction of whole.

Variables

SymbolDescriptionUnit
xxInput value
yyOutput value
kkConversion factor

Properties and Definitions

The volume and mass of a stockpile are influenced by the physical properties of the material being stored. Key factors include:

  • Angle of Repose: The steepest angle of descent or dip of the stockpile's slope relative to the horizontal plane, at which the material remains stable. This determines the stockpile's shape (e.g., conical) for a given material.
  • Bulking Factor: The ratio of the volume of loose stockpiled material to the volume of the same material in its natural or compacted state. When calculating mass from volume, use the loose bulk density, not the solid density.

Angle of Repose Data

The shape and stability of a stockpile are governed by the material's angle of repose. Below is data for common materials.

13 rows
Approximate Angle of Repose for Various Stockpiled Materials.
Material
Angle of Repose(degrees)
Ashes40
Cement (Portland)35
Clay (dry, lump)35
Coal (anthracite, lump)27
Coal (bituminous, lump)27
Coke (screened)31
Earth (dry, loose)30
Gravel (natural w/ sand)35
Gypsum (raw)40
Limestone (crushed)38
Sand (dry)34
Sand (wet)45
Wood chips45

Source: engineeringtoolbox.com

Mass Calculation Example

Building on the core formula from the Key Formulas section, the total mass (m) of a stockpile is found by multiplying its volume (V) by the material's bulk density (ρ).

m=ρVm = \rho \cdot V

Example: An anthracite coal stockpile (density ρ = 65 lb/ft³) is measured to have a conical shape with a diameter of 30 ft and a height of 8 ft. From reference charts, its volume (V) is approximately 2000 ft³. The total mass is calculated as:

m=(65lb/ft3)×(2000ft3)=130, ⁣000lbm = (65\,\text{lb/ft}^3) \times (2000\,\text{ft}^3) = 130,\!000\,\text{lb}

References