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Thrust Submerged Surface

Reference data and engineering information about thrust submerged surface for miscellaneous applications.

thrustsubmergedsurface

Overview

Engineering reference data for Thrust Submerged Surface in miscellaneous.

Key Formulas

Unit Conversion

y=xky = x \cdot k

Multiply by conversion factor.

Linear Interpolation

y=y1+(xx1)(y2y1)x2x1y = y_1 + \frac{(x - x_1)(y_2 - y_1)}{x_2 - x_1}

Estimate between two known points.

Percentage

p=partwhole×100%p = \frac{\text{part}}{\text{whole}} \times 100\%

Part as fraction of whole.

Variables

SymbolDescriptionUnit
xxInput value
yyOutput value
kkConversion factor

Examples

Thrust on a Vertical Submerged Surface

For a vertical surface with a linear pressure distribution, the average pressure acts at the centroid. The thrust force is:

F=ρg(ht+hb)2AF = \frac{\rho g (h_t + h_b)}{2} A

Calculation: For a surface 1 m wide and 2 m tall (ht=0h_t = 0 m, hb=2h_b = 2 m) submerged in water (ρ=1000 kg/m3\rho = 1000\ \text{kg/m}^3):

F=1000×9.81×(0+2)2×(1×2)=19620 N=19.6 kNF = \frac{1000 \times 9.81 \times (0 + 2)}{2} \times (1 \times 2) = 19620\ \text{N} = 19.6\ \text{kN}

Thrust on a Horizontal Submerged Surface

For a horizontal surface at constant depth, the pressure is uniform. The thrust force is:

F=ρghbAF = \rho g h_b A

Calculation: For a bottom surface 1 m × 2 m submerged 1 m deep in water:

F=1000×9.81×1×(1×2)=19620 N=19.6 kNF = 1000 \times 9.81 \times 1 \times (1 \times 2) = 19620\ \text{N} = 19.6\ \text{kN}

References