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Underground Pipe Pressure Soil Transport

Reference data and engineering information about underground pipe pressure soil transport for fluid mechanics applications.

undergroundpipepressuresoil

Overview

Engineering reference data for Underground Pipe Pressure Soil Transport in fluid mechanics.

Key Formulas

Reynolds Number

Re=ρvDμRe = \frac{\rho v D}{\mu}

Ratio of inertial to viscous forces — determines flow regime.

Bernoulli's Equation

P+12ρv2+ρgh=constP + \frac{1}{2}\rho v^2 + \rho g h = \text{const}

Conservation of energy for steady, inviscid, incompressible flow.

Continuity Equation

A1v1=A2v2A_1 v_1 = A_2 v_2

Conservation of mass for incompressible flow.

Darcy-Weisbach

ΔP=fLDρv22\Delta P = f \frac{L}{D} \frac{\rho v^2}{2}

Pressure drop due to friction in a pipe.

Variables

SymbolDescriptionUnit
ReReReynolds number
ρ\rhoFluid densitykg/m³
vvFlow velocitym/s
DDCharacteristic dimensionm
μ\muDynamic viscosityPa·s
PPPressurePa
ffDarcy friction factor

Transport Load Pressure

The pressure caused by surface transport depends on the wheel force and varies with burial depth. For standard calculations:

Reference wheel force: 75 kN (7,500 kg) with dynamic factor 1.75

The transport pressure decreases with depth. At 2 m burial depth, typical transport pressure is approximately 20 kPa for the reference loading condition.

Unit Conversions

FromToConversion
1 PaN/mm²10⁻⁶
1 PakPa10⁻³
1 Papsi1.450 × 10⁻⁴
1 kPakN/m²1

Design Guidelines

This calculation method is applicable for objects relatively small compared to burial depth. For underground pipes, the equations are valid when:

  • Pipe diameter is less than 300–500 mm
  • Burial depth significantly exceeds pipe diameter

Worked Example

Given: Pipe buried at 2 m depth, groundwater level at 1 m below surface

Soil pressure: psoil=(1800×9.81×1)+(1100×9.81×1)=28,449 Pa=28.5 kPap_{soil} = (1800 \times 9.81 \times 1) + (1100 \times 9.81 \times 1) = 28{,}449 \text{ Pa} = 28.5 \text{ kPa}

Water pressure: pwater=1000×9.81×1=9,810 Pa=9.8 kPap_{water} = 1000 \times 9.81 \times 1 = 9{,}810 \text{ Pa} = 9.8 \text{ kPa}

Transport pressure: ~20 kPa (from diagram at 2 m depth)

Total pressure: p=28.5+9.8+20=58.3 kPa58 kPap = 28.5 + 9.8 + 20 = 58.3 \text{ kPa} \approx 58 \text{ kPa}

References