Skip to main content
Speclore

Water Circulation Hot Water Boiler

Reference data and engineering information about water circulation hot water boiler for water systems applications.

watercirculationhotwater

Overview

Engineering reference data for Water Circulation Hot Water Boiler in water systems.

Key Formulas

Hydrostatic Pressure

P=ρghP = \rho g h

Pressure due to water column.

Flow Rate

Q=AvQ = A v

Area × velocity.

Variables

SymbolDescriptionUnit
PPPressurePa
QQFlow ratem³/s
hhHead/depthm

Water Flow Calculation

The relationship between boiler capacity (power), temperature drop, and water flow is governed by the heat transfer equation. For a water-based system, the formula is:

Q=m˙cΔTQ = \dot{m} \cdot c \cdot \Delta T

Where:

  • QQ is the heat transfer rate or boiler capacity (e.g., in kW, Btu/h).
  • m˙\dot{m} is the mass flow rate of water (e.g., in kg/s, lb/s).
  • cc is the specific heat capacity of water (approximately 4.18kJ/kg⋅K4.18 \, \text{kJ/kg·K} or 1Btu/lb⋅°F1 \, \text{Btu/lb·°F}).
  • ΔT\Delta T is the temperature drop of the water flow (e.g., in °C or °F).

Rearranging for water flow rate:

m˙=QcΔT\dot{m} = \frac{Q}{c \cdot \Delta T}

Unit Conversions

Key unit conversions for boiler capacity and flow:

  • 1gal (US)/min=6.30888×105m3/s=0.0227m3/h=0.06309dm3/s=2.228×103ft3/s=0.1337ft3/min=0.8327Imperial gal (UK)/min1 \, \text{gal (US)/min} = 6.30888 \times 10^{-5} \, \text{m}^3/\text{s} = 0.0227 \, \text{m}^3/\text{h} = 0.06309 \, \text{dm}^3/\text{s} = 2.228 \times 10^{-3} \, \text{ft}^3/\text{s} = 0.1337 \, \text{ft}^3/\text{min} = 0.8327 \, \text{Imperial gal (UK)/min}
  • 1hp (English horsepower)=745.7W=0.746kW=550ft⋅lb/s=2,545Btu/h1 \, \text{hp (English horsepower)} = 745.7 \, \text{W} = 0.746 \, \text{kW} = 550 \, \text{ft·lb/s} = 2,545 \, \text{Btu/h}
  • 1Btu/h=0.293W1 \, \text{Btu/h} = 0.293 \, \text{W}
  • 1kW=3,412Btu/h=1.341British hp1 \, \text{kW} = 3,412 \, \text{Btu/h} = 1.341 \, \text{British hp}

Example

Water flow through a boiler:
A boiler with capacity 50kW50 \, \text{kW} increases the temperature of circulated water by 20C20^\circ\text{C}. Using the formula with c=4.18kJ/kg⋅Kc = 4.18 \, \text{kJ/kg·K}:

m˙=50kW4.18kJ/kg⋅K20K=5083.6kg/s0.6kg/s\dot{m} = \frac{50 \, \text{kW}}{4.18 \, \text{kJ/kg·K} \cdot 20 \, \text{K}} = \frac{50}{83.6} \, \text{kg/s} \approx 0.6 \, \text{kg/s}

This result aligns with the provided data. For imperial units, use c=1Btu/lb⋅°Fc = 1 \, \text{Btu/lb·°F} and adjust capacity and temperature units accordingly.

References